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Update 20201107回溯周末总结.md
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problems/周总结/20201107回溯周末总结.md

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@@ -75,7 +75,7 @@ for (int i = startIndex; i < candidates.size() && sum + candidates[i] <= target;
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除了这些难点,**本题还有细节,例如:切割过的地方不能重复切割所以递归函数需要传入i + 1**
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所以本题应该是一个道hard题目了
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所以本题应该是一道hard题目了
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**本题的树形结构中,和代码的逻辑有一个小出入,已经判断不是回文的子串就不会进入递归了,纠正如下:**
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